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A math problem in senior one (about logarithm)
Solution: Because log4 3× log3 4 = 1, it is: 1/log4 3 = log3 4.

Therefore, a =1/log43+1/log73 = log34+log37 = log328.

Because 3 = log327 < log328 < log381= 4.

Therefore: A is in the interval (3, 4)

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