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Sub-heritage mathematics
We shouldn't be frightened by such a long topic. In fact, as long as we grasp the key points of the topic, calculate from the back to the front, and use the relevant knowledge of score application, we can easily solve it.

We might as well assume that this father has n sons, the last son is the nth son, and the penultimate son is the (n- 1) th son. Through analysis, we can know that:

The property jointly owned by the first son =1oox1+110 of the remaining property;

The property jointly owned by the second son =100× 2+110 of the remaining property;

The property share of the third son =1oo× 3+110 of the remaining property;

The (n- 1) joint property =100× (n-1)+10 of the remaining property;

The property jointly owned by the nth son is 100n.

Because each son's share of property is equal, that is,100× (n- 1)+10 = 100n of the remaining property, the (n-1) th son took100n.

Then, the remaining property is100 ÷110 =1000 kronor, and the last son gets 1000- 100 = 900 kronor. This shows that this father

(9OO ÷ LOO) = 9 sons, * * The remaining property is 9OO× 9 = 8 100 kroner.

If X is inherited, the boss gets100+(x-100) ÷10 = 90+x/10.

Second child score: 200+x-(90+x/10)-200 ÷10 =171+9x/100.

According to the meaning of the question, the equation is 90+x/10 =171+9x/100.

Solution: x=8 100 (krone)

Laudade: 90+8 100/ 10=900 (kroner)

8 100÷900=9 (piece)

A: The total amount of inheritance is 865,438+000 kroner, and 900 kroner is given to each of the nine children.