We might as well assume that this father has n sons, the last son is the nth son, and the penultimate son is the (n- 1) th son. Through analysis, we can know that:
The property jointly owned by the first son =1oox1+110 of the remaining property;
The property jointly owned by the second son =100× 2+110 of the remaining property;
The property share of the third son =1oo× 3+110 of the remaining property;
The (n- 1) joint property =100× (n-1)+10 of the remaining property;
The property jointly owned by the nth son is 100n.
Because each son's share of property is equal, that is,100× (n- 1)+10 = 100n of the remaining property, the (n-1) th son took100n.
Then, the remaining property is100 ÷110 =1000 kronor, and the last son gets 1000- 100 = 900 kronor. This shows that this father
(9OO ÷ LOO) = 9 sons, * * The remaining property is 9OO× 9 = 8 100 kroner.
If X is inherited, the boss gets100+(x-100) ÷10 = 90+x/10.
Second child score: 200+x-(90+x/10)-200 ÷10 =171+9x/100.
According to the meaning of the question, the equation is 90+x/10 =171+9x/100.
Solution: x=8 100 (krone)
Laudade: 90+8 100/ 10=900 (kroner)
8 100÷900=9 (piece)
A: The total amount of inheritance is 865,438+000 kroner, and 900 kroner is given to each of the nine children.