Take a woman as a whole, five men are arranged in a full array A66, and three women are arranged in a full array A33, so it is A66*A33.

Five people at both ends choose two C52s, and both of them rank A22, so these two people are: C52*A22. The remaining six people are all full, so it is (C52*A22)*A66.

First, five people form a complete A55. At this time, there are six positions (including the end) between men and women. First, select three positions C63. When women are full of A33, they are C63*A33. The result is: A55*(C63*A33).