Solution: First, change the general formula of this straight line into an inclined section:

y=-√3/3x-√3/3

So the slope of this straight line k =-√ 3/3.

The slope k of a straight line is the tangent of the inclination angle θ of this straight line, that is, tan θ =-√ 3/3.

Because the range of linear inclination is 0? ≤θ< 180?

So θ = 150?