S A-S B = 16
Then, the area of ABCD is added to S A and S B at the same time, and their difference remains unchanged.
(area of S A+trapezoidal ABCD)-(area of S B trapezoidal ABCD) = 16.
Namely: the area of ABCD-the area of -ABE = 16.
Suppose: CE is X.
(8+x)x6\2-8x6= 16
(8+x)x3-48= 16
x=38\3
CE is 38\3.