Current location - Training Enrollment Network - Mathematics courses - Solving the second root of mathematics in the second day of junior high school
Solving the second root of mathematics in the second day of junior high school
(a+√ab)/(√a b+b)+(√a b-b)/(a-√ab)a = 2+√3b = 2-√3

=[(a+√ab)(a-√ab)+(√a b+b)(√a b-b)]/[(√a b+b)(a-√ab)]

=(a^2-ab+ab-b^2)/(ab+a√ab-b√ab-ab)

=(a-b)(a+b)/[√ab(a-b) ]

=(a+b)/(√ab)

=(2+√3+2-√3)/[(2+√3)(2-√3)]

=4/(4-3)

=4

√ 18÷√8×√27

=3√2÷2√2×3√3

=(9√3)/2

5√(8/27)×√(4/3)×3√54

= 15√(8/27*4/3*54)

= 15√( 192/9)

= 15*8/3√3

=40√3

√6/(3√2-2√3)

=[√6(3√2+2√3)]/[(3√2-2√3)(3√2+2√3)]

=(6√3+6√2)/( 18- 12)

=6(√3+√2)/6

=√3+√2