Sixth grade math problems, problem-solving strategies and problem-solving process! ! Speed, you'd better tell me why you did it. You added 20 points! ! Use the solution to the problem.

(1) Two adults eat 1, two children eat 1, and three people just eat three.

So there is 99÷(2+ 1)=33 (adult)

33×2=66 (son).

Method 2: One adult eats two, and four children also eat two.

So an adult is equivalent to four children,

Suppose 99 people are all adults and want to eat 99×2= 198 (one).

Difference 198-99=99 (pieces)

Replace one adult with four children,

To change 99÷(4- 1)=33 (times),

So there are 33×2=66 children.

(2) Suppose 1 1 box of apples is removed, and there is18×11=198 (kg).

So the number of apple and pear boxes is the same,

Yes (1626-198) ÷ (18+24) = 34 (box)

So there are 45 boxes of apples and 34 boxes of pears.