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Third grade principal's math test paper
From the picture: 1 small rectangle =4 small rectangles.

The width of six small rectangles = the length of the big rectangle.

So: the width of the small rectangle = 18÷6=3dm.

Length =3×4= 12dm

Then the perimeter of the small rectangle =2×(3+ 12)

=2× 15=30dm

The circumference of a large rectangle =2×( 18+ 12)

=2×30=60dm