) 13 The answer is 1. Corresponding to the following, the mapping from p to m is () A.P={ positive integer}, M={- 1, 1}, F: X→ (- 1) XB. P = {Y2=|x| Answer: D Analysis: Because any non-zero real number in P has two opposite numbers in M. 2. In the following groups of functions, (a.f (x) = 1, g (x) = x0b.f (x) = x2, g (x) = only two functions with the same definition fields and corresponding rules are the same function. The domain of A.g(x) is X ≠ 0, that of f(x) is R.B.g(x) is x≠2, and that of F (x) is R. F( 1)=, and f (x 2) = f. Direct method: x =-1f (1) = f (-1) f (2) f (1) =-f (1) f (2) f (2) =. Let the quadratic function f(x)=ax2 bx c(a≠0), if f (x1) = f (x2) (x1≠ x2), then f(x 1 x2) is equal to. F (x1x2) = f () = c.5. If f(x)=-x2 2ax and g(x)= are all decreasing functions in the interval [1, 2], then the range of a is () A. (-65438. 0，f(2)& lt； F( 1), an image with a < f(x) is obtained, with its vertex abscissa x=a and its opening downward. Therefore, if f(x) is to be a decreasing function on [1, 2], there must be a≤ 1. To sum up, 0 < A≤ 1, d.6. (Nantong, Jiangsu, 2006) The inverse function of the function y=ln(x )(x∈R) is () A.y = (-), x ∈ Rb.y = (-). 0) The interval [0, 1] has a maximum value of -5, so the real number A is equal to () A.- 1 B.-C.D.-5 Answer: D Analysis: F (x) =-4x24ax-4a-A2 =-4 (x-). 0 & lt0,∴f(x) is a decreasing function on [0, 1]. ∴ f (x) max = f (0) =-4a-A2。 ∴-4a-A2 =-5 (A5) (A-65438+) 0, ∴ A =-5.8. Let f- 1(x) be the inverse of the function f(x)=log2(x 1). If the value of [1f-1(a)] [1] f (ab) is ... () a.1b.2c.3d.log23 Answer: bAnalysis: f-1. This shows that [1f-1.(0.1b.m ≥1c.m ≤1d.m ∈ r Answer: C analysis: ∵ y = LG (. λ2=, λ3=, define f(P)=(λ 1, λ2, λ3), if G is the center of gravity of △ABC, and f(Q)=,,, then () A. Point Q is in △GAB, B. Point Q is in △GBC, and C. Point Q is in. ), therefore, point G must be on a straight line parallel to AC and within △GAB, so choose A. Volume II (non-multiple choice question ***70 points) II. Fill-in-the-blank question (this big question ***4 small questions, 4 points for each small question, * *16 points) 165438+.
Answer: -(x≥4) Analysis: ∫ f (x-1) = x2-2x3 = (x-1) 22f (x) = x22, and x≤0, ∴ x-1≤ ∴ F (x) = X22 (x ≤- 1)。 ∴ F- 1 (x) =-(x ≥ 3) F-65438。
Answer: 15 Analysis: g (x) = 1-2x =, x =, f () =15.13. The function f(x) defined on r satisfies the relation: f (x) f (-x).
Answer: 7 Analysis: Let x=0, 0, 0, f( x) f(-x)=2, and get f () f () = 2, f () f () = 2, f () f () = 2, \.
Answer: 27 analysis: the equation x lgx=27 can be changed to lgx=27-x,
The equation x 10x=27 can be changed to10x = 27-X. Let f (x) = y=g(x, g (x) = 10x, and h (x) = 27-X. As shown in the figure below, it is obvious that x/kloc. Because the images of y=f(x) and y=g(x) are symmetrical about y=x, the straight line y=27-x is also symmetrical about y=x, and the straight line y=27-x has only one intersection with them, so these two intersections are about y=.