The first two digits are 8:
The probability that the first number is 8 is 1/9, and the probability that the second number is 8 is110.
The last six digits are randomly arranged.
So the probability of the first question is1/9 *110 =1/90.
2,
The opposite of the problem is that both numbers are greater than 8.
This probability is
Both digits are 9.
P= 1/90
So the initial probability is 89/90,
3. The probability that the first place is 1 is 1/9.
The probability that the second place is also 1 is110.
The same is P= 1/90.
There are nine groups of such numbers.
So the same probability is110.
P (different) =9/ 10