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Math homework?
The working efficiency of group 1.A is 20% higher than that of group B, so the time for processing 2 10 parts in group A is half an hour less than that for processing 200 parts in group B.. Assuming that group A and group B can process X and Y parts per hour, there are: X = (1+20%) * Y, 200/Y-2 10/X = 0.3. Second, a project can be completed by two engineering teams A and B working together for two days. If two teams do it alone, and team B spends one and a half days less than team A, how many days does it take for each team to do it alone? Assuming that it takes X and Y days for each team of A and B to finish it alone, there are:1(1/x+1/y) = 2, Y-X = 1.5. The distance between A and B is 80km, so take the bus from * * *. Assuming that the speed of cars and buses are xkm/s and ykm/s respectively, then there are: x=3*y, 80/y-80/x=2+40/60. Fourth, in order to prevent data input errors, two input personnel input the scores of 2640 students into the computer, and then let the computer compare whether the results of the two staff members are consistent. It is known that the input speed of A is twice that of B. As a result, A takes 2 hours less than B to complete the input. How many students' scores can two operators input per minute?