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Math problem in the second day of junior high school: Yuejin Automobile Sales Company went to an automobile factory to buy AB cars.
(1) let car a be x and car b be y.

10x+ 15y=300

8x+ 18y = 300 x = 150y = 100000。

(2) buy a car as a car.

15a+ 10(30-a)≦400

8000A+500A (30A) ≧ 204000A ≧ 18 A ≦ 20A

There are three schemes: Type A 65438 +08 Type B 65438 +02.

A car 19 B car 1 1.

20 vehicles of type A and 0 vehicles of type B 10.

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