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Answers to the third grade mathematics practice exam in primary school
Analysis:

Dad is required to be three times as old as Xiao Ming in a few years. First, how old was Xiao Ming at that time? Dad's age is three times that of Xiaoming, Xiaoming's age is 1 times, Dad is 3- 1 = 2 (times) older than Xiaoming, and his age is 38-8 = 30 (years old). Accordingly, what is the multiple of 1, that is, Xiao Ming's age at that time.

Solution: (38-8) ÷ (3- 1)

=30÷2

= 15 (years old) 15-8=7 years

7+38 = 45 years old

Seven years later, my father is three times as old as Xiaoming.