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Calculation: log29? log38 = a . 12b . 10c . 8d . 6
Answer to the question: D.

Problem analysis: Analysis: Write the real numbers of the two logarithmic formulas given in the problem as 32 and 23 respectively, then put the exponent of the real number in front of the logarithmic sign, and then find the value of the original formula according to the reciprocal of logab and logba.

Answer: log29

log38=2log23

3log32=6。

So choose D.

Comments: This question examines the application of the formula for changing the bottom. The key to solve this problem is to grasp that logab and logba are reciprocal and basic problems.