Firstly, it is proved that △ Abd △ BCE is because AB = BC ∠ ABC = ∠ ACB = 60 BD = CE.

So AD=BE

Equilateral delta △ADF

So AD=DF

So BE=DF

Because △ Abd△ BCE

So ∠ bad = ∠ CBE ∠ ADB = ∠ BEC ∠ C = ∠ ADF = 60.

So ∠ FBD+∠ BDF = 180.

So parallel equals DF.

Parallelogram BDFE

So ∠EFD=∠EBD

Look at you. It was months ago.-I'm dizzy.