Because BD=DE=EC, it can be concluded that the area of △PCE = 13△PBC, then the area of △PCE = 14△BCG.

Because AF=FG=GC, the area of △BCG = 13△ABC,

So the area of △PEC is 1 12 of the area of △ABC.

Then the shaded area is the area of △ABC:112+112 =16,

1× 16= 16,

A: The shaded area in the figure is 16.