Three students, A, B and C, donated some books to the corner of the class library. A donated twice as many books as B, and C donated fewer books than B. If all of them are added up, the number is a prime number not exceeding 50, and the sum of the numbers is 1 1. How many books did each of the three students donate? How many books did three people donate?

The result is a prime number not exceeding 50, and the sum of all digits is 1 1.

This number is 47.

If c donated five copies,

Then Party B donates (47-5) ÷ (1+2) = 42 ÷ 3 =14 copies.

A donated 14×2=28 copies.

If c donated eight copies,

Then Party B donates (47-8) ÷ (1+2) = 39 ÷ 3 =13 copies.

A donated 13×2=26 copies.

If c donates 1 1 copy,

Then Party B donates (47-11) ÷ (1+2) = 36 ÷ 3 =12 copies.

A donated 12×2=24 copies.

Therefore, students A, B and C donated 28, 14, 5 or 26, 13, 8 or 24, 12,1kloc-0/books, and three students donated 47 books.