(b5hh？ Xiaolin's house, Xiaohua's house and library are in a straight line in turn. At the same time, Xiao Lin and Xiao Hua walked out of the house at a constant speed.

Solution: (1)-ea÷e=6a (m/min)

(a-e)×6a= 96a (m)

6a× a= 1-aa (m).

So the answer is 6a, 96A, 1-AA.

(a) y 1 (meters) and x (minutes? The functional relationship of) is: y 1=eax.

The image of the function is the line segment m.

(3)∵ Kobayashi's speed is 6a m/min, and Xiaohua's walking speed is ea m/min.

y=eaxy=6ax？ An ea,

D: X = 1-Y = E8A。

So Xiaohua 1 set off, and one minute later the two schools met on the road.